Hardware » Helios

#include <stdio.h>

#include <time.h>

#include <termios.h>

#include <errno.h>

#include <fcntl.h>

#include <QList>

float E12[]

{

   100, 120, 150, 180, 220, 270, 330, 390, 470, 560, 680, 820,

   1000, 1200, 1500, 1800, 2200, 2700, 3300, 3900, 4700, 5600, 6800, 8200,

   10000, 12000, 15000, 18000, 22000, 27000, 33000, 39000, 47000, 56000, 68000, 82000,

};

float E24[]

{

   100, 110, 120, 130, 150, 160, 180, 200, 220, 240, 270, 300, 330, 360, 390, 430, 470, 510, 560, 620, 680, 750, 820, 910,

   1000, 1100, 1200, 1300, 1500, 1600, 1800, 2000, 2200, 2400, 2700, 3000, 3300, 3600, 3900, 4300, 4700, 5100, 5600, 6200, 6800, 7500, 8200, 9100,

   10000, 11000, 12000, 13000, 15000, 16000, 18000, 20000, 22000, 24000, 27000, 30000, 33000, 36000, 39000, 43000, 47000, 51000, 56000, 62000, 68000, 75000, 82000, 91000

};

#define E E12

float r2( float target, float r1 )

{

   return( r1 * ( ( target / 1.23 ) - 1 ) );

};

float voltage( float r1, float r2 )

{

   return(1.23 * ( 1 + ( r2 / r1 ) ) );

};

float r_ges(float r1, float r2)

{

   // https://studyflix.de/elektrotechnik/parallelschaltung-widerstand-4533

   return( ( r1 * r2 ) / ( r1 + r2 ) );

}

int main()

{

   float target=12.0;

   int bestR1=-1;

   int bestR2=-1;

   int bestR3=-1;

   float bestVoltage=1000000;

   float v;

   int count=sizeof(E)/sizeof(E[0]);

   //printf("%g Ohm\n", r2(target, 1000.0) );

   for(int i1=0; i1<count; i1++)

   {

      // if( ( E[i1] >= 1000 ) && ( E[i1] <= 5000  ) )

      if( E[i1] == 1000 )

      {

         for(int i2=0; i2<count; i2++)

         {

            for(int i3=0; i3<count; i3++)

            {

               v=voltage( E[i1], r_ges( E[i2], E[i3] ) );

               printf("%g V\n", v );

               if( ( v >= target ) && ( v < bestVoltage ) )

               {

                  bestR1=i1;

                  bestR2=i2;

                  bestR3=i3;

                  bestVoltage=v;

               }

            }

         }

      }

   }

   printf("%d/%d/%d\n", bestR1, bestR2, bestR3 );

   printf("R1=%g\n", E[bestR1] );

   printf("R2=%g\n", E[bestR2] );

   printf("R3=%g\n", E[bestR3] );

   printf("[R2|R3]=%g\n", r_ges( E[bestR2], E[bestR3] ) );

   //v=voltage(E[bestR1], E[bestR2] );

   v = bestVoltage;

   printf("Result=%g; %g%%\n", v, (v-target)*(100/target) );

   // References from TI:

   // 3.3 V R2 = 1.7 k

   // 5 V, R2 = 3.1 k

   // 12 V, R2 = 8.84 k

   // 15 V, R2 = 11.3 k

   // For ADJ. Version R1 = Open, R2 = 0 Ω Patent Pending

   v=voltage(1000, 8840);

   v=voltage(1000, 3100);

   v=voltage(1000, 11300);

   printf("Reference=%g\n", v);

   return 0;

}